Jawaban Latihan UAS Petra Manyar Fisika Kelas 10

1.V air tumpah = V2 a - V2 p = 1(1 + 2 x 10-4 x 80 ) - 1 (1+ 3 x 3 x 10-6 x 80 )
                                               = 1,016 - 1,00072 = 0,01528 L

2. Q lepas = Q terima
    m x c x delta t = m x c x delta t
    60 x (n82 - t ) = 300 ( t - 10 )
                       t = 22 derajat celcius

3. Q lepas = Q terima
    ma x ca x delta t = mes x ces x delta t + mes x Les + mes x c air x delta t air
   500 x 1 x 30       =   n x 0,5 x 20         + n x 80       +  n x 1 x 50
                          n  = 107,14 gram

4. Q total = mes ( ces x delta t + L           + c air x delta t + U            + c uap x delta t )
                = 0,05 (3100 x 20   + 334000 + 4200 x 100  + 2256000 + 2010 x 20 )
                = 154.160 Joule

5. n1 = 1,5 R1 = -10 cm R2 = -30 cm
    1/f = (n2/n1 -1 ) ( 1/R1 + 1/R2)
         = (1,5/1 -1 ) ( -1/10 - 1/30)
         = -2/30
     f = -15 cm

6. (Q/t) a = (Q/t) b
    (ka x Aa x delta ta)/ l a = (kb x Ab x delta tb)/ lb
      ka ( 80- t )                 = 2 ka ( t - 5 )
                                   t    = 30 derajat celcius

7. fob = 10 mm fok = 25 mm Sob = 10,5 mm , berakomodasi maks
    1/S'ob = 1/10 - 1/10,5
               = 5/1050
    Jadi  S'ob = 210 mm
    1/Sok = 1/25 - (-1/250) = 11/250
    Jadi Sok = 22,727 mm

    d = S'ob + Sok = 210 + 22,727 = 232,727 mm
    M = S'ob/Sob ( Sn/fok + 1 )
         = 210/10,5 (250/25 + 1 )
         = 220 x

8. 1/fu : 1/fa = ( nl/nu - 1 ) : ( nl/na - 1 )
     fa : 20     = ( 1,6/1 - 1 ) : ( 1,6/1,33 - 1 )
            fa     = 59,11 cm

9. B

10. B

11. C

12.        R al                                                  = R cu
           rho x l/a                                              =   rho x l/a
      (2,65 x 10-8) : (1/4 phi x d al pangkat 2)  =  (1,72 x 10-8) : (1/4 phi x 2 pangkat 2)
                                                               d al  = 2,48 mm

13. delta R     = R1 x alfa x delta t
      10,4 - 10 = 10 x alfa x 20
      alfa = 0,002/derajat delcius

      R2 = R1 ( 1 + alfa x delta t )
            = 10 ( 1 + 0,002 x 50 )
            = 11 ohm

14. a. Rs1 = 2 + 4 = 6 ohm Rs2 = 4 +8 = 12 ohm
          R penganti = (12 x 6) : ( 12 + 6 ) = 4 ohm

      b. Ra = (1 x 2 ) : ( 1 + 2 + 3) = 1/3
          Rb = (1 x 3 ) : ( 1 + 2 + 3) = 1/2
          Rc = (2 x 3 ) : ( 1 + 2 + 3) = 1
          Rs1 = Rb + 4 = 0,5 + 4 = 4,5 ohm
          Rs2 = Rc + 5 = 1 + 5 = 6 okm
          1/Rp1 = 1/Rs1 + 1/Rs2 = 2/9 + 1/6 = 7/18 , Rp1 = 18/7 ohm
          R pengganti = Ra + Rp1 = 1/3 + 18/7 = 61/21 ohm

15. R1 = 200 kuadrat : 60 = 666,67 ohm
      R2 = 240 kuadrat : 100 = 576 ohm
      V = 480 volt
      a. I = E : ( R + r ) = 480 : 1242,67 = 0,386 Ampere
          I = I1 + I2 = 0,386 Ampere ( seri )
          V1 = 0,386 x 666,67 = 257,335 Volt
          V2 = 0,386 x 576 = 222,336 Volt

      b. P = I kuadrat x Rs
             = 0,386 (pangkat 2) x 1242,67
             = 185,153 watt

16. W1 = 5 x 20 x 6 x 30 = 18000 Wh = 18 kwh
      W2 = 100 x 2 x 30 = 6000 Wh = 6 kwh
      W3 = 40 x 24 x 30 = 28800 Wh = 28,8 kwh
      W4 = 60 x 4 x 30 = 7200 Wh = 7,2 kwh
       W total = 60 kwh
       Biaya = W x Rp 500,- = 60 x 500 = Rp 30.000,-

17. W = Q
      I (pangkat 2) x R x t      = m a x c a x delta t + H x delta t
      I (pangkat 2) x R x 120 =  1 x 4200 x 20     + 60 x 20
                                        R = 710 ohm

18. R6 = 5 ohm ; I = 50 A ; V6 = 10 mV = 0.01 V
      I6 = V6 : R6 = 0,01 : 5 = 0,002 A
      R shunt = RG : ( n - 1 ) = 5 : ( 2500 - 1 ) = 2,04 x 10-3 ohm
      n = I / IG = 5 / 0,002 = 2500

19.R1 = 8 ohm ; I2 = 0,5 A ; V1 = 4 volt
     V2 = V3 = V4 = 4 Volt
     1/Rp1 = 1/8 + 1/16 + 1/16 = 1/4 ohm ; jadi Rp1 = 4 ohm
     I1 = 4/4 = 1 Ampere = I5 = I seri 1
     R seri 1 = 20 + 4 = 24 ohm
     1/Rp2 = 1/9 + 1/18 = 1/6 ; jadi Rp2 = 6 ohm
     R seri 2 = 6 + 6 = 12 ohm
     I seri 1 : I seri 2 = 1/24 : 1/12 = 1 : 2
     I seri 1 = 1/3 x I            I seri 2 = 2/3 x 3
          1    = 1/3 x I                        = 2 A
           I    = 3 A
  
     V x a = Iseri 2 x Rp2
               = 2 x 6 = 12 volt

20. -9 + 4 + I ( 4 + 0,5 + 0,5 ) x 0
          -5   + 5 I   = 0
                       I = 1 Ampee

       V ac       = sigma E + sigma I R
       Va - Vc = -9          +  1 ( 4 + 0,5 )
       Va - 0    = -9 + 4,5
                 Va = -4,5 Volt